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soal logaritma
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Topic: soal logaritma (Read 6407 times)
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joniwjy
Newbie
Posts: 1
soal logaritma
«
on:
June 24, 2016, 10:23:13 AM »
alo gan, ini ada soal gimana selesaikan:
jika
2
log 3 = a dan
7
log 3 = b, maka
63
log 14 = ....
mohon bantuannya gan, tq
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riani
Newbie
Posts: 1
Re: soal logaritma
«
Reply #1 on:
June 28, 2016, 09:24:13 PM »
@joniwjy
ini d pernah w pelajari wkt kelas x
63
log 14= (
3
log14)/(
3
log63) 3 nya ambil dari angka paling sering muncul
= (
3
log 2 +
3
log7)/(
3
log7 +
3
log9) angka 14= 2*7 dan 63 9*7
=(1/a + 1/b)/(1/b +
3
log3
2
)
2
log3=a maka
3
log 2 = 1/a
=(1/a + 1/b)/(1/b + 2) ruas atas dan bawah dikali ab
=(b + a)/(a + 2ab)
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soal logaritma